Question

What is a polynomial function in standard form with zeroes 1,2,-3, and -3

Answer 1

Is one of the threes positive?

Answer 2

yes

Answer 3

would the answer be g(x) x^4-3x^3-7x^2+15x+18

Answer 4

Ok, work backwards then. To get those answers the polynomial factored would be (x-1)(x-2)(x-3)(x+3)

Answer 5

so then Im right or not

Answer 6

Almost, the 15x and +18 isnt right

Answer 7

should it have been -15x+18

Answer 8

x^4-3x^3-7x^2+27x-18

Answer 9

that one is not an option

Answer 10

ill check again

Answer 11

ok have options
x^4+3x^3-7x^2-15x+18
x^4+3x^3-7x^2+2x+18
x^4-3x^3+7x^2+15x+18
x^4-3x^3-7x^2+15x+18

Answer 12

Im still getting x^4-3x^3-7x^2+27x-18

The problem was find the polynomial with zeroes 1,2,3,-3?

Answer 13

what is a polynomial function in standard form with zeroes 1,2,-3, and -3

Answer 14

hey its x^4+3x^3-7x^2-15x+18

Answer 15

Looks like option 1!

Answer 16

how did you get that if you dont mind me asking

Answer 17

i had option 4

Answer 18

see the zeroes mean those values will make the eqn=0
Thus, the equation is (x-1)*(x-2)*(x+3)*(x+3)

Answer 19

oh ok that where i messed up I had -3

Answer 20

have another question if you have time

Answer 21

sure fire :)

Answer 22

find all the zeroes of the equation
x^3+x^2=-3x-3

Answer 23

wait....on it

Answer 24

x^2[x+1]=-3[x+1]
=> [x+1][x^2+3]
=> x=-1 the other 2 roots are complex :/

Answer 25

my choices are
i sgrt 3, -i sgrt 3, -1
i sgrt 3, -i sgrt 3, 1
sgrt 3, - sgrt3, -1
i sgrt 3, 1

Answer 26

option 1 is right!

Answer 27

ok thanks do you have time for one more problem

Answer 28

:)