Question

Find the sum series
4
∑
k-1 = (k+4)^2

Answer 1

\[\sum_{k=1}^4(k+4)^2\]?

Answer 2

yes thats how it looks i need help

Answer 3

\[\Large \sum_{k=1}^{4}(k+4)^2 = (1+4)^2 + (2+4)^2 + (3+4)^2 + (4+4)^2\]

Answer 4

the problem is cut off at the end

Answer 5

= (1+4)² + (2+4)² + (3+4)² + (4+4)²

Answer 6

i got 125

Answer 7

Well, I got 174.

(1+4)² + (2+4)² + (3+4)² + (4+4)² = 5² + 6² + 7² + 8² = 174

Answer 8

so do i type the term of the series