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Chemistry 18 Online
OpenStudy (anonymous):

........

OpenStudy (saifoo.khan):

So we have to make 2 equations?

OpenStudy (anonymous):

yes i think we have to make to separate equation

OpenStudy (saifoo.khan):

Because methane burns in oxygen, not in water.

OpenStudy (anonymous):

but i don't know how to do this problem

OpenStudy (saifoo.khan):

I think there's some mistake in the question.

OpenStudy (anonymous):

well maybe, but this is a homework question and its in the book

OpenStudy (anonymous):

sorry

OpenStudy (saifoo.khan):

Oh. lol. My bad then.

OpenStudy (anonymous):

oh don't worry

OpenStudy (anonymous):

so you don't know how to do it?

OpenStudy (saifoo.khan):

Sorry no.

OpenStudy (saifoo.khan):

And we can find amount of heat by bond energies or by Q=mcT.

OpenStudy (anonymous):

This is the hint given when i enter the answer, determine the heats of combustion for both methane and water gas, where the gas can be treated as the sum of the heats of combustion of water and CO individually. For the water gas, two moles total of product are made, so the sum of the heats of combustion must be manipulated to give a value for one mole.

OpenStudy (saifoo.khan):

Wait! Have they given you values for the formation of CO2 and H2O? Or values for combustion for C or H?

OpenStudy (anonymous):

noo, they didn't gave me any values

OpenStudy (saifoo.khan):

Then how on the Earth they want us to solve this? D:

OpenStudy (anonymous):

yeah i know, this question are not clear

OpenStudy (saifoo.khan):

Hmmm. :/

OpenStudy (saifoo.khan):

Hydrocarbon + O2 => H2O + CO2 heat

OpenStudy (anonymous):

ok, the heat of combustion for hydrogen is -285.8 KJ/mol

OpenStudy (saifoo.khan):

Meaning, the formation of H2O is that..

OpenStudy (saifoo.khan):

Unfortunately, i have to leave. I'll see this problem tomow if you have time.

OpenStudy (anonymous):

yes

OpenStudy (saifoo.khan):

Oh man. :/ Sorry. If you get a chance, post it's solution here. -Cheers.

OpenStudy (anonymous):

hmm i don't know if i would be able to get the solution :/

OpenStudy (saifoo.khan):

Alright then. No prob. :)

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