Two urns contain white balls and yellow balls. The first urn contains 3 white balls and 6 yellow balls and the second urn contains 3 white balls and 8 yellow balls. A ball is drawn at random from each urn. What is the probability that both balls are white? A. B. C. D.
A.2/33 B.1/9 C.1/11 D. 3/10
first event probability of choosing white ball = 3/9 = 1/3 second .......................................................... = 3/11 since the 2 events are independent the probabilities are multiplied so can you find the correct one?
b.1/9
Is that correct?
no whats 1 / 3 * 3/11
no whats 1 / 3 * 3/11
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those are the 2 probabilities which are multiplied to get the required probability
those are the 2 probabilities which are multiplied to get the required probability
can you do that computation?
can you do that computation?
I come out with 1/11
right - multiplying gives 3/33 which equals 1/11
right - multiplying gives 3/33 which equals 1/11
thank you
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