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The solution of the equation 2/(5x+5)-3/(x^2-1)=4/(x-1)
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\[\frac{2}{5(x+1)} - \frac{3}{(x+1)(x-1)} = \frac{4}{x-1}\]
Multiply both sides by x + 1 to get: \[\frac{2}{5} - \frac{3}{x-1} = \frac{4(x+1)}{x-1}\]
Add 3/(x+1) to both sides to get: \[\frac{2}{5} = \frac{4(x+1)}{x-1} + \frac{3}{x-1}\]
Combine fractions on the right side to get: \[\frac{2}{5} = \frac{4x + 4 + 3}{x-1}\] Simplify the numerator get: \[\frac{2}{5} = \frac{4x + 7}{x-1}\]
Cross Multiply to get: 2(x-1) = 5(4x + 7)
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Expand both sides to get: 2x - 2 = 20x + 35 Place like terms on the same side to get -35 - 2 = 20x - 2x -37 = 18x
Finish solving for x from there.
are you going to divide 18 by 37
No, you're going to divide both sides by 18 to isolate x
-37/18
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