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ln(4x+15)=7
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Do \[\ln(e^{4x+15})=e^7\]
you subtract 15 on both sides. so that's going to be 4x = -8. so then what you do is you divide 4 on both sides so you should get x = -2
Not quite..^ The ln and e on the right on the equation i wrote above cancels out, leaving you with 4x+15=e^7 4x=e^7-15 x=(e^7-15)/4
where did u get e though? and sorry. I wasn't sure if that ln is included in the original equation.
No. Take anti log of both tems,i.e. e^Ln(4x+15) = e^7. This evaluates to (4x+15)=e7. Now subtract 15 from both sides and divide eveything by 4. x = (e^7)-15/4
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ln is the natural log, its the same as \[\log _{e}\]
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