A student wearing frictionless in-line skates on a horizontal surface is pushed by a friendwith a constant force of 43 N. How far must the student be pushed, starting from rest, so that her final kinetic energy is 350 J ?

Question

A student wearing frictionless in-line skates on a horizontal surface is pushed by a friendwith a constant force of 43 N.  How far must the student be pushed, starting from rest, so that her final kinetic energy is 350 J ?

anonymous · Answer

use can use work-energy theories
w=theta Ke
Fd=Ke2-Ke1
43*d=350-0

anonymous · Answer

okay I don't really understand how can you explain it a little more

anonymous · Answer

w=F*d
newton second law F=dp/dt=d(mv)/dt
we get
w=(d(mv)/(dt))*d, d=v*dt
w|dw:1353897203006:dw|=d(m*v^2)