Question

Could someone explain how to take the arcsin of both sides (inverse sine) for step #3 of this problem (in order to solve for t?
10 = 12 + 2.83 sin[(2*pi/365*(t-365)]

step 1: -2 = 2.83 sin[(2*pi*/365)(t-365)]
step 2: -0.7067 = sin[(2*pi*/365)(t-365)]
step 3: sin[(2*pi*/365)(t-365)] = -0.7848
Solve for t.

[(2*pi*/365)(t-365)] = -0.90244
Use the first value

t-365 = -52
t = 313 days

Answer 1

you need to sue a calculator to find \(\sin^{-1}(-0.7846)\)

Answer 2

*use

Answer 3

ah, i see now. thanks!!

Answer 4

yw