Question

(x+2)(x-2)>3x solve the quadratic inequality and write answer in interval notation.

Answer 1

\[x^2-4>3x\]\[x^2-3x-4>0\]\[(x-4)(x+1)>0\]Solving each factor:
\[x-4>0\]\[x>4\]and,\[x+1>0\]\[x>-1\]The only way x can be greater than -1 AND greater than 4 is if it is greater than 4. Thus x>4. In interval notation: \[(4,\infty)\]

Answer 2

thank you.

Answer 3

your welcome

Answer 4

you're*