Given C = 118, B = 50, and c = 15, use the law of sine to solve the triangle for the value of a... would I use the formula a/ sin A = b/ sin B?
sin C/c = sin B/b
A^2=B^2+C^2-2ab cos a
hero I used that formula earlier and I got b = 6.355932203
i know i have to plug this in to a/ sin A = b/ sin B but I keep getting the wrong answer
118 + 50 + A = 180 solve for A
\[\frac{b}{\sin(50)}=\frac{15}{\sin(118)}\] \[b=\frac{15\sin(50)}{\sin(118)}\] make sure your calculator is in "degree" mode since you are working with degrees
i get something pretty close to 13 http://www.wolframalpha.com/input/?i=15sin%2850%29%2Fsin%28118%29
I'm used to the sin being on the top, not the bottom. Guess it really doesn't matter
okay I worked it all out and i got a = 3.12?? but I know that's not right..
Did you find angle A?
yes. C is 118 and B is 50. I added those together and subtract it from 180 and it gave me 12
Angle A is so small. I expect its side to be small as well.
yes. so I have a/12 = 13/50...I multiply 12 and 13 and got 156. divide that by 50 i get 3.12..but that's not the right answer
Must be the ambiguous case
my choices are 17.29, 4.76, 4.07, 2.31, 3.53...obviously its not going to be 17.29
so that can be ruled out
this line so I have a/12 = 13/50 is not correct
what was my mistake?
we found \(b\) right? \(b=13\)
yes and the formula is a/ sin A = b/ sin B
ok so \(\frac{a}{\sin(15)}=\frac{13}{\sin(50)}\) making \(a=\frac{13\sin(50)}{\sin(15)}\)
okay, so im confused as of what to do here. divide?
first of all you are supposed to ignore me because that equation was wrong
\(\frac{a}{\sin(15)}=\frac{13}{\sin(50)}\) so \(a=\frac{13\sin(15)}{\sin(50)}\)
that is better
i got 3.9 now
i get \(4.4\) rounded http://www.wolframalpha.com/input/?i=13sin%2815%29%2Fsin%2850%29
are you using a calculator? easier to put it in wolfram in one step
yes i am..and neither of the answers we are getting is one of my choices..
what are your choices for \(b\) ?
i only have choices for a since that is what i am looking for. when i solve for b i got 6.38..idk how you are getting 13
ok lets go slow, see if we made any mistakes you have \(C=118^o, c=15, A=50^o\) is that right?
no B = 50, not A
sat, only 1, A = 12 so u have sin 12, not sin 15
oh ok \(B=50^o\) and so \(A=12^o\)
yes
@hartnn so it is!!!
yes, and now u get an answer which is in choices..
then we know \(\frac{a}{\sin(12)}=\frac{15}{\sin(118)}\) and so \[a=\frac{15\sin(12)}{\sin(118)}\]
i get \(3.53\) http://www.wolframalpha.com/input/?i=15sin%2812%29%2Fsin%28118%29
yup, thats it.
I got the same too, finally! thank you!
imagine!
Well, at least the right answer was found
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