perform the indicated operations & simplify the result. Leave the answer in factored form. ((x/x+4) + 1) / ((12/x^2-16) + 1)
It might be easier to see like this: \[\frac{\frac{x}{x+4}+1}{\frac{12}{x^{2}-16}+1}\]
yeah, I wasn't sure how to type it in like that :/
No worries.
Actually, I'd probably write it a differnt way initially.
i wouldn't add
\[\left(\frac{x}{x+4}+1\right) \div\ \left(\frac{12}{x^2-16} + 1\right)\]
There. That's much better
Now add, then divide
i would start with \[\frac{\frac{x}{x+4}+1}{\frac{12}{(x-4)(x+4)}+1}\] and multiply numerator and denominator by \((x+4)(x-4)\) cancelling merrily as i went along
I'm trying to keep it simple @satellite73
\[\frac{\frac{x}{x+4}+1}{\frac{12}{(x-4)(x+4)}+1}\times \frac{(x+4)(x-4)}{(x+4)(x-4)}\] i think this is simpler, but that is of course a matter of taste
that makes so much sense @satellite73 !! I didn't even think to factor the other denominator! been working at this package for far too long
get rid of the compound fraction in one step, then multiply out, combine like terms etc
you get \[\frac{x(x+4)+(x+4)(x-4)}{12+(x+4)(x-4)}\] and then you can do the algebra top and bottom
\[\left(\frac{x}{x+4}+\frac{x+4}{x+4}\right) \div\ \left(\frac{12}{x^2 - 16} + \frac{x^2 - 16}{x^2 - 16}\right)\]
I was trying to multiply everything by \[x^{2} - 16\] ..silly girl
\[\left(\frac{2x + 4}{x+4}\right) \div\ \left(\frac{x^2 -4}{x^2 - 16} \right)\]
\[\left(\frac{2x + 4}{x+4}\right) \times\ \left(\frac{x^2 -16}{x^2 - 4} \right)\]
And you can still cancel from there
My method isn't too bad either
I wish I could give myself a medal
@refusetofail not silly at all that is what i did, it is just easier to see if when it is in factored form
so.. wait, I'm kind of confused how to get the actual answer through the simplification..
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