find an equation for the line with the given properties

perpendicular to the line x-8y=6 containing the point (2,3)

I changed the equation to y=(x+6)/-8 but I'm kind of stuck as to what I'm supposed to next

Question

find an equation for the line with the given properties

perpendicular to the line x-8y=6 containing the point (2,3)

I changed the equation to y=(x+6)/-8 but I'm kind of stuck as to what I'm supposed to next

hero · Answer

How about 

$$y = -\frac{x}{8} - \frac{3}{4}$$

anonymous · Answer

so would the slope be -1? where the reciprocal, if it were perpendicular would be 1?

hero · Answer

Remember

$$\frac{a + b}{c} = \frac{a}{c} + \frac{b}
{c}$$

hero · Answer

The slope is -1/8. Do you see that?

hero · Answer

Maybe if I wrote it this way:

$$y = -\frac{1}{8}x - \frac{3}{4}$$

anonymous · Answer

oooooo.. rioght.. so then the reciprocal would be 8/1??

hero · Answer

Precisely

anonymous · Answer

so how would that work, to find the "points".. put the equation as y=8x-3?

hero · Answer

You cannot assume what b is. All you know is the slope and the given point: so 

y = 8x + b

insert the given point to find b

anonymous · Answer

so b=-13?

hero · Answer

Would you like to show how you got b = -13?

anonymous · Answer

if the points were (2,3)
and then equation I had was y=8x+b

3=8(2)+b, solve and then the new equation is y=8x-13?

anonymous · Answer

or no....?

hero · Answer

Good job

anonymous · Answer

yay :) perpendicular equations always confused me, and now they've come back to kick my in the butt

hero · Answer

Nah, they're easy. Plus, when you start helping others with similar problems, they get even easier.

anonymous · Answer

thanks :)

hero · Answer

That's it? No more questions?

anonymous · Answer

hah, hold on