complete the square
(6r^2+6r+12) = 0

Question

complete the square 
(6r^2+6r+12) = 0

anonymous · Answer

I attempted this but I checked online and got a different answer. I need some kinda of guidance to see who's right.

hartnn · Answer

you can first factor out 6, what u get ? 
and whats your attempt ?show your work till now, so that we can rectify.

anonymous · Answer

I got r=-(1/2)+or-$$\sqrt{(1/12)}$$ i

hartnn · Answer

u just need to complete the square, right ? 
or u need to solve ?

anonymous · Answer

solve by completing the square

hartnn · Answer

so, 
(6r^2+6r+12) = 0
r^2 +r +2 = 0
right ?

anonymous · Answer

thats what I got

anonymous · Answer

then I moved the 2 to the other side, then took the 1 and divided by two, then squared and got r^2 + r + (1/4)= -(1/2)

hartnn · Answer

on right side, its 
-2 +1/4 = .... ? 
its not -1/2

anonymous · Answer

I thought you had to multiply the (1/4) by 6 since we factored that out

hartnn · Answer

6 is gone, forget it... 
x^2 + x= -2 
to complete square, u juast add 1/4 on both sides.

anonymous · Answer

my teacher told me to multiply the (1/4) by the 6 that we factored out. :O

hartnn · Answer

i don't think that correct...

anonymous · Answer

oky, so now we have r^2 +r +(1/4)= -(7/4)

hartnn · Answer

yes. -7/4 is right .

hartnn · Answer

r^2 +r +(1/4) = (.....)^2

anonymous · Answer

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