PLEAAASSEEE help Pre Calc:
thank you so much picture posted below
xoxo vvv
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
you first have to use the pythagorean theorem to find the length of AB
jimthompson5910 (jim_thompson5910):
AC^2 + BC^2 = AB^2
36^2 + 24^2 = x^2
1296 + 576 = x^2
keep going to solve for x
OpenStudy (anonymous):
x=+/- 12 to the power of 13
OpenStudy (anonymous):
@jim_thompson5910
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jimthompson5910 (jim_thompson5910):
you mean \[\Large x = \pm 12\sqrt{13}\] right?
OpenStudy (anonymous):
yes :) @jim_thompson5910
jimthompson5910 (jim_thompson5910):
since AB is the length and x is the length, we only consider positive lengths
so \[\Large x = 12\sqrt{13}\]
which means \[\Large AB = 12\sqrt{13}\]
jimthompson5910 (jim_thompson5910):
now use the definition of sine, plug in the lengths, and simplify
sin(angle) = opposite/hypotenuse
sin(A) = 24/(12*sqrt(13))
sin(A) = 2/(sqrt(13))
sin(A) = (2*sqrt(13))/(sqrt(13)*sqrt(13))
sin(A) = (2*sqrt(13))/(13)
OpenStudy (anonymous):
ughhh thank you so much! FINALLY I understand this nonsense.
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