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Mathematics 15 Online
OpenStudy (anonymous):

In triangle ABC, measure of angle A=33, a=12,b=15, what is the measure of angle b to the nearest degree?

OpenStudy (anonymous):

@geoffb

OpenStudy (anonymous):

Are you given a diagram? You should be able to use sin, cos, or tan to find angle B, since you know two sides (a and b).

OpenStudy (anonymous):

|dw:1353915380080:dw|

OpenStudy (anonymous):

Does it look like that?

OpenStudy (anonymous):

If so, use a rule like \(\tan B = \frac{15}{12}\), though it might be different depending on your diagram.

OpenStudy (anonymous):

my diagram looks exactly like yours

OpenStudy (anonymous):

Perfect! You can solve for B using \(\tan^{-1} (\frac{15}{12})\) then.

OpenStudy (anonymous):

i got a long decimal, although the choices im giveb are all whole numbers

OpenStudy (anonymous):

Okay, wait... If the triangle was a right-angle triangle, you could have solved for B by simply subtracting 90-33. So I imagine that's not the case. It's not a right-angle triangle, I'm guessing.

OpenStudy (anonymous):

wait, dont i use the law of sine?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

idk man do you know why i keep getting the decimal, all im doing is putting in the inverse of tan(15/12) into my calculator

OpenStudy (anonymous):

No, forget I said that. That was for a right-angle triangle. Like you said, you need to use the law of sines. \(\Large\frac{a}{\sin A} = \frac{b}{\sin B}\) \(\Large\frac{12}{\sin 33} = \frac{15}{\sin B}\)

OpenStudy (anonymous):

\[\sin B = \frac{15 \sin 33}{12}\]

OpenStudy (anonymous):

Is 43 one of the possible answers?

OpenStudy (anonymous):

yea, so i dont find the inverse?

OpenStudy (anonymous):

Yes, you do. We got: \[\sin B = \frac{15 \sin 33}{12}\] so... \[B = \sin^{-1} (\frac{15 \sin 33}{12})\]

OpenStudy (anonymous):

I see now, thanks out :D

OpenStudy (anonymous):

No problem. Have a good night. :)

OpenStudy (anonymous):

same for you :)

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