solve the equation
(1/3)^(3x+6) = 9x-5

Question

solve the equation
(1/3)^(3x+6) = 9x-5

anonymous · Answer

Is that really the equation?

anonymous · Answer

yeeep...$$(\frac{ 1 }{ 3 } )^{3x+6} = 9x-5$$

hartnn · Answer

then it does not have any closed form...can't be solved http://www.wolframalpha.com/input/?i=%281%2F3%29%5E%283x%2B6%29+%3D+9x-5

anonymous · Answer

apparently the answer is x=4/5

anonymous · Answer

i just dont know how to get there

hartnn · Answer

with that equation, not possible. 
make sure u have typed the question correctly, i would suggest  to take the screenshot.

anonymous · Answer

it's from a textbook..

anonymous · Answer

@refusetofail, ur equation is correct it's an exponential equation

calculusfunctions · Answer

@refusetofail @hartnn was right. You did not write the question clearly. Since now you're offline I will just do this one.

$$\left( \frac{ 1 }{ 3 } \right)^{3x +6}=9^{x -5}$$$$(3^{-1})^{(3x +6)}=(3^{2})^{(x -5)}$$$$3^{-3x -6}=3^{2x -10}$$The bases are equal, thus equate the exponents and solve for  x.  Thus$$-3x -6=2x -10$$Adding  10  and  3x  to both sides yields$$10-6=2x +3x$$$$4=5x$$Dividing both sides by  5  yields$$x =\frac{ 4 }{ 5 }$$

And that is the answer thou protested!

hartnn · Answer

still have doubt with that ^ ?

anonymous · Answer

omg, thankfully I figured this one out on my own at about 3am this morning, because the exact same one was on my final!