Question

Find the surface area of the portion of z=4-x^2-y^2 above the xy-plane.

Answer 1

\[\int\int\sqrt{1+(f_x)^2+(f_y)^2}~dA\]

Answer 2

z=0 when x^2+y^2 = 4

Answer 3

then integrate with respect to x and y?

Answer 4

f(x,y,z)=4-x^2-y^2

fx=-2x

fy=-2y

fz = 1, which is already expressed in the general setup

Answer 5

yes