6 friends (Andy, Bandy, Candy, Dandy, Endy and Fandy) are out to dinner. They will be seated in a circular table (with 6 seats). Andy and Bandy want to sit next to each other to talk about the Addition Principle, Bandy and Candy want to sit next to each other to talk about the Principle of Inclusion and Exclusion. How many ways are there to seat them?

Clarification: Rotations are counted as the same seating arrangements, reflections are counted as different seating arrangements.

Question

6 friends (Andy, Bandy, Candy, Dandy, Endy and Fandy) are out to dinner. They will be seated in a circular table (with 6 seats). Andy and Bandy want to sit next to each other to talk about the Addition Principle, Bandy and Candy want to sit next to each other to talk about the Principle of Inclusion and Exclusion. How many ways are there to seat them?

Clarification: Rotations are counted as the same seating arrangements, reflections are counted as different seating arrangements.

anonymous · Answer

lets see
the number of ways to seat n people around a circle is $(n-1)!$ you can treat andy brandy and candy as one person, and get $2!=2$ but then andy can candy can switch places, ( brandy has to sit between them) so i think the answer is $2\times 2=4$ 
since 4 is such a small number you can probably draw a diagram and see if it is correct

anonymous · Answer

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anonymous · Answer

but answer is not 4

anonymous · Answer

are in the question Andy and Bandy together as well as Bandy and Candy together...

anonymous · Answer

well if so 
then the reqd no of seating is 6

anonymous · Answer

no its not 6