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simplify into radical form √-48
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\[\sqrt{-48}=\sqrt{16\times 3\times -1}=4\sqrt{3}i\]
You have a negative number under the radical therefore your answer is going to be complex. \[\sqrt{-48} = \[i \sqrt{48} = i \sqrt{4^{2}*3} \] Find the biggest perfect square that is a factor or 48? which is 16 = 4^2
i guess is skipped a step \[\sqrt{16\times 3\times -1}=\sqrt{16}\times \sqrt{3}\times \sqrt{-1}=4\sqrt{3}i\]
Thank you @philo1234 @satellite73 and @bigrobot69 lol
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