Question

The rocket-driven sled Sonic Wind No. 2, used for investigating the physiological effects of large accelerations, runs on a straight, level track that is 1080 m long. Starting from rest, it can reach a speed of 1560 km/h in 1.70 s.
a) Compute the acceleration in m/s^2.
b) Compute the acceleration in g’s.
c) What is the distance covered in 1.70s?

Answer 1

a)v=u(starting speed which in this case =0)+at
for converting the km/h to m/s multiply by 1000/3600
b)1 meter / (second^2) = 0.101971621 g
c)s=ut(again 0) +at^2/2

Answer 2

for c
distance = 0 + (26(1.7)6^2)/2
right?

Answer 3

d= 0+(26/2)(1.7^2)

Answer 4

yep, if the acc is 26m/s^2, i haven't checked, yet your logic is right.

Answer 5

do you know what a is?

Answer 6

acceleration

Answer 7

yes

Answer 8

cos i dont think 26 is the accerelation

Answer 9

a)Okay, first you have that 1560 km/h = 433.333333 meters / second. Then using v=at you find that the acceleration is 433.333333/1.7 = 254.901961m/s^2
b)1 meter / (second^2) = 0.101971621 g
c)s=254.901/2*(1.7)^2 m

Answer 10

thank you