The heights of female students at a northeastern college are approximately normally distributed with mean 64.5 inches and standard deviation 1.8 inches. According to the normal distribution, what is the approximate percentage of female students with heights between 62 and 63 inches? Round your answer to the nearest integer.

Please help an explanation of how to get the solution along with it would be greatly appreciated?

Question

The heights of female students at a northeastern college are approximately normally distributed with mean 64.5 inches and standard deviation 1.8 inches. According to the normal distribution, what is the approximate percentage of female students with heights between 62 and 63 inches? Round your answer to the nearest integer.

Please help an explanation of how to get the solution along with it would be greatly appreciated?

highlyeducated87 · Answer

What subject is this i know math but what part

anonymous · Answer

Statistics.

highlyeducated87 · Answer

Oh ok

anonymous · Answer

I have no clue as to how I go about solving this?

anonymous · Answer

Do you know anything about normal distributions?

highlyeducated87 · Answer

I forgot how to do it i need my memory to be refreshed

anonymous · Answer

no I know how to look up a z score. I am pretty sure the normal distribution has something to do with the mean of the data? I am very confused

anonymous · Answer

Good. So we have to standardise our current model to N(0,1) using:
$$z = (x - \mu )/ \sigma $$

anonymous · Answer

They gave us mu 64.5 and sigma 1.8.
So you can just plug in 63 and 62 and it's the difference.
Does that help?

amistre64 · Answer

does your class use a stats program; or calculator (ti83), or do you have to do it all from tables?