Question

Kind of stuck on this one! Please check what I have so far? :) Thanks!

Solve x2 + 4x + 8 = 0

x= -2 + 4i

Answer 1

if \(-2+4i\) is right then the other answer is \(-2-4i\)

Answer 2

My answer was x= -2 + 4i

Answer 3

\[x^2+4x+8=0\]
\[x^2+4x=-8\]
\[(x+2)^2=-8+4=-4\]
\[x+2=\pm\sqrt{-4}\]
\[x+2=\pm2i\]
\[x=-2\pm2i\]

Answer 4

i think you forgot the square root and write \(\sqrt{-4}=-4i\) but it should be \(\sqrt{-4}=\sqrt{4}\sqrt{-1}=2i\)

Answer 5

quadratic formula will give the same result, but in this case it is easier to complete the square, because the middle term \(4x\) has an even coefficient

Answer 6

My mistake, i didn't even catch onto that error! wow thank you for making sense of this!!!!!!!