Kind of stuck on this one! Please check what I have so far? :) Thanks!

Solve x2 + 4x + 8 = 0

x= -2 + 4i

Question

Kind of stuck on this one! Please check what I have so far? :) Thanks!

Solve x2 + 4x + 8 = 0

x= -2 + 4i

anonymous · Answer

if $-2+4i$ is right then the other answer is $-2-4i$

anonymous · Answer

My answer was x= -2 + 4i

anonymous · Answer

$$x^2+4x+8=0$$
$$x^2+4x=-8$$
$$(x+2)^2=-8+4=-4$$
$$x+2=\pm\sqrt{-4}$$
$$x+2=\pm2i$$
$$x=-2\pm2i$$

anonymous · Answer

i think you forgot the square root and write $\sqrt{-4}=-4i$ but it should be $\sqrt{-4}=\sqrt{4}\sqrt{-1}=2i$

anonymous · Answer

quadratic formula will give the same result, but in this case it is easier to complete the square, because the middle term $4x$ has an even coefficient

anonymous · Answer

My mistake, i didn't even catch onto that error! wow thank you for making sense of this!!!!!!!