Question

please please help:) medals rewarded
find x

a. 8
b. 8sqrt3
c. 16 sqrt3
d. 1.8 sqrt3

Answer 1

You have an angle, as well as hypotenuse and the opposite leg. Which function do you use when you have opposite and hypotenuse: sine, cosine, or tangent?

Answer 2

this is geometry

Answer 3

Okay, then you need to know the rules of a 30-60-90 triangle.

Answer 4

Do you know how the three legs of a triangle relate?

Answer 5

not reaally but kinda

Answer 6

The ratio between short leg : long leg : hypotenuse is \(1 : \sqrt{3} : 2\).

Answer 7

Knowing that, you can use Pythagoras to solve for \(x\). Being across from the 60º angle, would it be the long leg or the short leg?

Answer 8

long?

Answer 9

Right.

Answer 10

so wouldnt the answer be B to this question?

Answer 11

?

Answer 12

That's what I get, yes, since \(\large x = \frac{\sqrt{3}}{2}(h)\)

Answer 13

wouldnt it be B?

Answer 14

As I said, yes.

\[\large x = \frac{\sqrt{3}}{2}(h) = \frac{16\sqrt{3}}{2} = 8\sqrt{3}\]

Answer 15

oh sorry their was a freezing problem! thanks so much:)

Answer 16

No problem. It's being slow on my side, too. Have a good day. :)

Answer 17

yes you to!!!:)