Is the answer to sqrt x + sqrt x-3=3 11/2?
To check you renter your solution back into the original equation \[\sqrt{\frac{ 11 }{ 2 }}+\sqrt{\frac{ 11 }{ 2 }-3}=3.926...\] which is not 3
sorry top line was suppose to say: To check your solution renter it back into the original equation
Where did I go wrong? I screwed up the problem somehow.
well use the equation editor to show me the steps you took to solve the problem
\[\sqrt{x}+\sqrt{x-3}=3\]
\[\left( \sqrt{x} \right)^{2}+(\sqrt{x-3})^{2}=\left( 3 \right)^{2}\]
\[x+x-3=9\]
stop that is where you went wrong
\[2x-3=9\]
Okay. What do I do?
you are squaring the entire side \[(\sqrt{x}+\sqrt{x-3})^{2}=3^{2}\] not your earlier step but I think this will give you more problems then it will solve give me a second and I will see if I can find an easier path t lead you down
okay
\[\sqrt{x}+\sqrt{x-3}=3\] is this your equation?
yes
It might help me if you tell me what the title of the section this question is under is.
Equations with radicals. It just asks to solve the following equations.
what techniques have you been taught?
Well, when it comes to problems like this, all I've learned is to square both sides and go from there but apparently, I'm not very good at it.
I need to close this one to find help with another one but if you could continue helping me with this one, that would be great! :)
I know the answer is 4 by graphing but I cannot see the algebraic method for some reason
oh
@hba this may be too easy for you but fr some reason I cannot see the algebraic way to solve this question so that I can lead him through it. It has been too long since I have had to solve radicals without calculus.
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