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In the reaction of Ca(OH)2(s) + HNO3 ? + ?, how many grams Nitric acid will be required to completely neutralize 100 grams of Calcium Hydroxide? (need to balance) (A) 55.19g (C) 110.38g (B) 220.77 g (D) 63.02g
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I tried to figure this one out but I don't get any of the answers listed. Here's my working out for what it's worth: 1 mole of Calcium hydroxide is 74g so 74g of calcium hydroxide reacts completely with 2 moles of nitric acid or 2 times 63 grams. If I divide 100 by 74 and multiply 63 by 2 then by the answer I get is 170g.
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