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\[3x ^{1/3}+2x ^{1/3}-5=0\]
x=1
.....show your work please
@jim_thompson5910
You can combine the cube root of x Therefore you get 5cube root of x -5=0 5 cube root of x= 5 Divide both sides by 5------>cube root of x =1------->x=1
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Sorry I did it on my phone so it does not have enough math functions. It is hard to type:)
yeah....its kinda weird im not sure i get it
@jim_thompson5910
let z = x^(1/3) to get 3z+2z-5=0 now solve for z
oh ok use the substitusion ok thx
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wait what is the sub for 1/3 and 2/3
2/3??
3x^1/3+2x^2/3-5
i don't see a 2/3 in 3x ^(1/3)+2x ^(1/3)-5=0
3x ^(1/3)+2x ^(2/3)-5=0 becomes 3z+2z^2-5=0
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u would still use 1/3 right?
oh..
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