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Mathematics 10 Online
OpenStudy (anonymous):

I will post the question is the comments

OpenStudy (anonymous):

\[3x ^{1/3}+2x ^{1/3}-5=0\]

OpenStudy (anonymous):

x=1

OpenStudy (anonymous):

.....show your work please

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

You can combine the cube root of x Therefore you get 5cube root of x -5=0 5 cube root of x= 5 Divide both sides by 5------>cube root of x =1------->x=1

OpenStudy (anonymous):

Sorry I did it on my phone so it does not have enough math functions. It is hard to type:)

OpenStudy (anonymous):

yeah....its kinda weird im not sure i get it

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

let z = x^(1/3) to get 3z+2z-5=0 now solve for z

OpenStudy (anonymous):

oh ok use the substitusion ok thx

OpenStudy (anonymous):

wait what is the sub for 1/3 and 2/3

jimthompson5910 (jim_thompson5910):

2/3??

OpenStudy (anonymous):

3x^1/3+2x^2/3-5

jimthompson5910 (jim_thompson5910):

i don't see a 2/3 in 3x ^(1/3)+2x ^(1/3)-5=0

jimthompson5910 (jim_thompson5910):

3x ^(1/3)+2x ^(2/3)-5=0 becomes 3z+2z^2-5=0

OpenStudy (anonymous):

u would still use 1/3 right?

OpenStudy (anonymous):

oh..

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