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Mathematics 15 Online
OpenStudy (anonymous):

anthony has 10 ft of framing and wants to use it to make the largest rectangleular picture frame possible. find the maximum area that can be enclosed by his frame

OpenStudy (anonymous):

call l=length and w=width. We have two relations, one for the perimeter:\[10=2l+2w\]and one for the area:\[A=lw\]We can express w in terms of l using the perimeter equation:\[w=5-l\]Thus:\[A(l)=l(5-l)\]So minimize the area function with respect to l...good from here?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

k, you're welcome :)

OpenStudy (anonymous):

thnks ur awesome

OpenStudy (anonymous):

so my aweser would be 1 ?

OpenStudy (anonymous):

never computed it...hang on...on the phone

OpenStudy (anonymous):

k

OpenStudy (anonymous):

haha

OpenStudy (anonymous):

I get a max area of 25/4 which occurs when length=2.5ft and width=2.5ft

OpenStudy (anonymous):

not sure where you got 1 from

OpenStudy (anonymous):

idk etherir

OpenStudy (anonymous):

but anyways thanks man (or girl )

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