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anthony has 10 ft of framing and wants to use it to make the largest rectangleular picture frame possible. find the maximum area that can be enclosed by his frame
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call l=length and w=width. We have two relations, one for the perimeter:\[10=2l+2w\]and one for the area:\[A=lw\]We can express w in terms of l using the perimeter equation:\[w=5-l\]Thus:\[A(l)=l(5-l)\]So minimize the area function with respect to l...good from here?
yes
k, you're welcome :)
thnks ur awesome
so my aweser would be 1 ?
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never computed it...hang on...on the phone
k
haha
I get a max area of 25/4 which occurs when length=2.5ft and width=2.5ft
not sure where you got 1 from
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idk etherir
but anyways thanks man (or girl )
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