Find the zeros of f(x)=x^2-2x-8
There is a website called mathway.com that you can usually type problems like this into and it'll automatically compute the answer for you.
Factor the expression gives \[x^2-2x-8 = (x+2)(x-4)\] And we notice that for this expression to give 0, either (x+2) has be to 0, or (x-4) has to be 0. Hence the zeros are -2 or 4
Okay thank you. So you telling me that the zeros of this functions is -2 or 4?
There are 2 zeros, and they are -2 AND 4 :)
How do I figure it how? how do you work this problem?
okay thank you . but how did you get -2 and 4
One way is to write: (x )(x ) Then you think about which 2 numbers multiply together gives -8 and add up together gives -2
So you might think 1 and -8 multiply each other gives -8, but add up doesn't give -2, then you take another couple of numbers and check if it works, then you find out the only couple that works are 2 and -4
Okay thank you. what if I had a simpler problem like find the zero(s) of f(x)= 3x-2.. How would you work this problem??
You want 3x -2 = 0 in this case. Add 2 to both sides to get 3x = 2 and then divide both sides by 3 to get your answer.
Which would be 2/3??
@brooke_tessa Basically, finding zeroes is just another way of saying: when x=?, the whole expression equals to 0?
it would just be like the following: f(x)=3x-2 *set it to 0 0=3x-2 x=2/3
Yes...nice job!
OKAY! Thank y'all. so if I had a problem like f(x)= -4x + 6 -6= -4x = 6/4 = 3/2 ???? IS THAT RIGHT??
yes :)
OKAY!!! THANK YALL SO MUCH FOR THE HELP! I UNDERSTAND (:
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