Question

Find area of y= 11/ (x^3)+5x between 1 and 2

Answer 1

i'm not sure what to do next

Answer 2

did you get
\[\frac{11}{5}\left(\frac{1}{x}-\frac{x}{x^2+5}\right)\]?

Answer 3

yea, i think that's what i have at the bottom of the page

Answer 4

i just ignored the 11 for now

Answer 5

so it is basically 11/5

Answer 6

ok then the anti derivative of \(\frac{1}{x}\) is \(\ln(x)\) and the anti derivative of \(\frac{x}{x^2+5}\) requires a simple u sub

Answer 7

i dont get the x/ x^2+5 part

Answer 8

you can almost do it in your head \(u=x^2+5, du=2xdx, \frac{1}{2}du=dx\)
the anti derivative is \(\frac{1}{2}\ln(u)=\frac{1}{2}\ln(x^2+5)\)

Answer 9

i should have written \(\frac{1}{2}du=xdx\) sorry

Answer 10

oh ok , get it thanks!

Answer 11

@satellite73 can u plz check if i have done it correctly?