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How do you work out lim (n/n+1) as n goes to infinity? I think it's supposed to be 1.
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1/(1+1/n)->1
Yes indeed :)
@kmccullo Have you learnt derivatives yet?
numerator and denominator have same degree (they are both 1) so it is the ratio of the leading coefficients which in this case is \(\frac{1}{1}=1\)
Got it! Divided numerator and denominator by 1/n! Thanks!
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no need for calculus, although you can use it imagine if you will \(n=1000000\) then you get \(\frac{1000000}{1000001}\) which is pretty close to 1
Generally when you encounter a limit in exam that you aren't sure of, simply plug numbers in your calculator to verify your answer :)
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