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Solve. 3x2 + 12x = 3
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i bet you can do this divide by 3 first
then, because the middle term is going to have an even coefficient (namely 4) solve by completing the square
divide 12 by three?
i can walk you through it if you like or else you can try first
I'll come up with an answer first :)
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divide everything on both sides of the equal sign by 3, everything
The expression is the same as: \[3x^2+12x−3=0\] Now notice they all can divide by 3, we get \[x^2+4x−1=0\] Now use the technique I taught you in your last 'finding zero' question
Nevermind, use the quadratic formula
-2 _+_ sq root 3
nop :(
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\[x^2+4x=1\]\[(x+2)^2=1+4=5\] \[x+2=\pm\sqrt{5}\]
ughh let me try again!!!1
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