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Trigonometry 18 Online
OpenStudy (anonymous):

how do i simplify trig identities

OpenStudy (anonymous):

sec(x)-cos(x)/tan(x)

hartnn (hartnn):

write tan x as sin x/cos x

OpenStudy (anonymous):

(sec(x)-cos(x))/(sin(x)/cos(x))

hartnn (hartnn):

yes, now multiply cos x in numerator and denominator.

OpenStudy (anonymous):

working.

OpenStudy (anonymous):

(sec(x)cos(x)-cos^2(x))/sin(x)

hartnn (hartnn):

sec x cos x = 1

hartnn (hartnn):

and whats 1-cos^2x = .... ?

OpenStudy (anonymous):

you may also write cos x as 1/sec x

OpenStudy (anonymous):

@hartnn 0?

hartnn (hartnn):

no, \(\sin^2x+cos^2x=1\) so whats 1-cos^2 x= ?

OpenStudy (anonymous):

sin^2x

hartnn (hartnn):

yes. so now what is sin^2 x / sin x =?

OpenStudy (anonymous):

(2sin(x))/(sin(x))

hartnn (hartnn):

?

OpenStudy (anonymous):

no

hartnn (hartnn):

sin^2 x = sin x* sin x

OpenStudy (anonymous):

sin^2 x / sin x =

OpenStudy (anonymous):

working

OpenStudy (anonymous):

oh so it would just be sin x

hartnn (hartnn):

yes.

OpenStudy (anonymous):

my bad i was thinking of bringing the exponent down, thanks for your time

hartnn (hartnn):

welcome ^_^

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