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how do i simplify trig identities
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sec(x)-cos(x)/tan(x)
write tan x as sin x/cos x
(sec(x)-cos(x))/(sin(x)/cos(x))
yes, now multiply cos x in numerator and denominator.
working.
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(sec(x)cos(x)-cos^2(x))/sin(x)
sec x cos x = 1
and whats 1-cos^2x = .... ?
you may also write cos x as 1/sec x
@hartnn 0?
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no, \(\sin^2x+cos^2x=1\) so whats 1-cos^2 x= ?
sin^2x
yes. so now what is sin^2 x / sin x =?
(2sin(x))/(sin(x))
?
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no
sin^2 x = sin x* sin x
sin^2 x / sin x =
working
oh so it would just be sin x
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yes.
my bad i was thinking of bringing the exponent down, thanks for your time
welcome ^_^
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