Question

What is the solution of the following system?
-3x - -2y= -12
9x + 6y = -9

Answer 1

is there a typo in this problem because i see 2 minus's?
well anyways what you want to do is on the first equation solve for y then plug it into the 2nd equation and solve for x
then plug that x value into the first equation and solve for y to get your answers

Answer 2

one is a minus and one is a negative

Answer 3

ok so when you subtract a negative it becomes a positive so your first equation is
-3x + 2y = -12
9x + 6y = -9

multiply first eq by 3

-9x + 6y = -12
9x + 6y = -9
add them
12y = -21
y = -21/12 = -7/4

substitute in 1st equation

-3x + 2(-7/4) = -12
-3x + -7/2 = -12
-3x = 17/2
x = -17/6

Answer 4

(2, 1)
no solutions
(–2, –1)
infinitely many solutions
so than witch answer could it be?

Answer 5

sorry i made a typo in my work

-3x + 2y = -12
9x + 6y = -9

y = -6 + 3/2(x)
9x+6(-6+3/2(x)) = -9
9x - 36 + 9x = -9
18x = 27
x = 1.5

-3(1.5) + 2y = -12
y = -3.75

might of made a mistake
neeed someone to double check