not good at visualizing stuff like this, any help would be wonderful!! A park in a subdivision is triangular-shaped. Two adjacent sides of the park are 533 feet and 525 feet. The angle between the sides is 53°. Find the area of the park to the nearest square foot.
t would be wonderful if someone could help me work through it
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thats cool! how did you do that?
There's a drawing to help you visualize it. The adjacent sides are next ot each other and the 53 deg angle is in between them.
Use draw at the bottom.
so its just A= b x h / 2, uhm any chance you can tell me what i use for the height?
The formula for the area of a triangle given two sides (a and b) and included angle C is: \[A = \frac{ 1 }{ 2 } ab \sin C\]
shoot.. i really hate sine, cosine, and tangents :(
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don't worry about it anymore it will take forever for me to understand, thanks for your help though i appreciate it alot!
In drawing above, sin C = h/a (opposite over adjacent) Solve for h: h = a sin C Area of triangle = (1/2) bh, but h = a sin C, so Area = (1/2) ab sin C
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