Question

how can i derivate the following derivative?
[ (√25 + x^2)/2] + [(6-x)/4]

Answer 1

\[\frac{\sqrt{25+x^2}}{2}+ \frac{6-x}{4}\]Like this?

Answer 2

\[\frac{ \sqrt{25 + x ^{2}} }{ 2 } + \frac{ 6-x }{ 4 }\]

Answer 3

yeah!

Answer 4

I'll do it this way:
\[\Large \frac{2\sqrt{25+x^2}+6-x}{4} \]

Answer 5

Now:
\[\Large \frac{1}{4} \times [\frac{d}{dx} 2(25+x^2)^{0.5}+6-x]\]

Answer 6

Can you solve now?

Answer 7

but how did u get the \[\frac{ 1 }{ 4 }\] ??

Answer 8

Did you understand the first step? I took LCM in it.

In next step, since constants stay the same, i took it out.

Answer 9

You can write my second step as:
\[\Large [2\sqrt{25+x^2}+6-x] \times [\frac{1}{4}]\]

Answer 10

ooh, i understood, ill try to do the following,,, :) thank you very much

Answer 11

You're welcome. :)

Answer 12

Sure. Where are you stuck?

Answer 13

uhmm once im trying to solve the derivative i get stuck!, i get something like this\[\frac{ 1 }{ 4\sqrt{25+x ^{2}} }-\frac{ 1 }{ 4 }\] is that right?

Answer 14

You should get:
\[\frac{x}{2\sqrt{x^2+25}}- \frac14\]

Answer 15

uhm how did u get that? :$

Answer 16

Let me show it to you.

Answer 17

I'll attach a photo.

Answer 18

yepp, thank you so!

Answer 19

thank you so much!! uhmm but i got a question, why you get 0.5 in the denominator?

Answer 20

0.5 = 1/2
same thing.

Answer 21

Like if i multiply "a" with 0.5, i will get 0.5a or 1/2 a