Question

What are the x– and y–intercepts of the graph of y = 2x^2 – 8x – 10?

Answer 1

The axis of symmetry for the first equation would be x = 3.

To find the x intercepts of y = 2x^2 - 8x - 10, we need to set the left side to zero and solve:
y = 2x^2 - 8x - 10
0 = 2x^2 - 8x - 10
0 = (2x + 2)(x - 5)

2x + 2 = 0
2x = -2
x = -1

x - 5 = 0
x = 5

So, the x intercepts are -1 and 5

To find the y intercepts, we need to set x = 0 in the equation and solve for y:
y = 2x^2 - 8x - 10
y = 2(0)^2 - 8(0) - 10
y = -10

So, the y intercept is -10

I leave the last problem to you, since you need to explain why you chose the method that you did. Good luck! MY MEDAL

Answer 2

thank you so much you are a big help(:

Answer 3

ANOTHER QUESTION PLEASE CAN HELP YOU

Answer 4

What is the axis of symmetry of the graph of y = –3(x + 8)^2 + 5?

Answer 5

It is x=-8
when x=-8+a and x=-8-a
y will get the same value = -3a^2 + 5

Answer 6

thanks