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Chemistry 16 Online
OpenStudy (anonymous):

A sample of 76 g of NaCl is dissolved to make 1 L of solution. What is the molarity of the solution? Show your work.

OpenStudy (anonymous):

\[?mol NaCl = 76gr NaCl \times (\frac{ 1mol NaCl }{ 58.5gr NaCl }) = 1.30 mol NaCl\] [NaCl] = \[1.30 mol NaCl \div 1L solution = 1.30 mol.L ^{-1}\]

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