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Trigonometry 9 Online
OpenStudy (anonymous):

Simplify the trigonometric expression. (cos(x)/sec(x))+(sin(x)/csc(x))

OpenStudy (anonymous):

cos x/ (1/cos x) + sin x/ (1/sin x)

OpenStudy (anonymous):

im having trouble with the common denominator

OpenStudy (campbell_st):

sec = 1/cos and scs = 1/sin so so you have \[\frac{\cos(x)}{\frac{1}{\cos(x)}} +\frac{\sin(x)}{\frac{1}{\sin(x)}} \] the rule for dividing by a fraction is to flip and multiply hope this helps as the answer should become obvious...

OpenStudy (anonymous):

working...

OpenStudy (anonymous):

just 1 x 1?

OpenStudy (campbell_st):

nope its \[\cos(x) \times \frac{\cos(x)}{1} + \sin(x) \times \frac{\sin(x)}{1} = \]

OpenStudy (anonymous):

=1

OpenStudy (campbell_st):

now it should become really obvious... its interesting in that your answer is correct but your working is all wrong...

OpenStudy (campbell_st):

1 is the correct answer... and it uses the identity \[\sin^2(x) + \cos^2(x) = 1\]

OpenStudy (anonymous):

weird, i'll keep working on it i have a few more problems to work on

OpenStudy (anonymous):

thanks for your time

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