Question

Please help!!! I can't figure this one out... You are counting all the ways to create a list of five-letter strings of characters using only the following letters: {a, b, c, d, e, m, n, o, p, q, u, y, z} How many ways can you create a five-letter string of characters when you have these conditions: Must start with a vowel or y. Must end with a consonant or y. Must have the letter x in the middle position. Enter the numerical value in the answer box.

Answer 1

what ahve you tried already?

Answer 2

is the intent to have groups of five letters, or is duplicating elements feasible?

Answer 3

I'm geting thrown off by the x - it is not on the list so I am assuming that it is just intended to be there? I assume duplicating is ok because it doesn't say that it's not...

Answer 4

well, if x is not a typo, either in the list or on the information part; then there are exactly no ways to get an x in the middle

Answer 5

So the answer would be 0? I've tried entering that and it says it is not right.

Answer 6

then the question is simply written badly unless there is something that you are not sharing from it

Answer 7

No, that is exactly how it is written.

Answer 8

i see 13 elements; and 5 positions; i believe, if repetition is alliowed .... i wanna say that amounts to 13^5 ways, but the subject is a little hazy. I recall somethings about P and C and such ....

Answer 9

"How many ways can you create a five-letter string of characters" lol, i spose thats not really one of the questions tho

Answer 10

Must start with a vowel or y, 5 elements

5*13*13*13*13

Answer 11

lol... I am so frustrated wtih this question. I've tried everything to solve it and every answer I type is is not correct. I am at a loss.

Answer 12

Must end with a consonant or y; there are 9 elements to that

13*13*13*13*9

have you tried moving to the next question?

Answer 13

can you offer up a screenshot?

Answer 14

Yes, I have and I keep coming back to it because it is the last one to complete. It is holding me up being able to submit the assignment and and I don't want to give up! lol. Yes I can. Hold on for one moment.

Answer 15

spose you had 2 elements, {0,1} how many ways can you create groups of 3 that end in a 1?

001
011
101
111

2*2*1 = 4 ways

spose you had 3 elements, {0,1,a} how many ways can you create groups of 4 that start with a 0?

1*3*3*3 = 27 is my guess, lets see

0000 0110 0a10
0001 0111 0a11
000a 011a 0a1a
0010 01a0 0aa0
0011 01a1 0aa1 = 27
001a 01aa 0aaa
0100 0a00 00a0
0101 0a01 00a1
010a 0a0a 00aa

Answer 16

hmm, a spose that means that all 3 conditions must hold?

Answer 17

well, lets try this; using the same concept as i portrayed;

5 elements avaliable for the start position
9 elements for the end position
1 element for the middle position (assuming it needs to be an x)
and 13 elements for the other 2 positions each

5*13*1*13*9 = ?

Answer 18

I tried 27 and it said it is not correct. Hold please and I'll try this last one...

Answer 19

27 was just an example to see if my memory wasnt failing me :)

Answer 20

Haha!! ! I am getting desperate! the last one we tried.

Answer 21

you say youve already tried: 5*13*1*13*9 ?

Answer 22

Yes, it's not correct... Grrr!

Answer 23

well, its only worth 1 pt .... id say let it go into the etheral abyss :)

Answer 24

I know! I'm stubborn though! lol I hate to lose points. lol

Answer 25

Thank you for trying!