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Mathematics 4 Online
OpenStudy (anonymous):

omgosh hep please 1. Find the value of x and y.

OpenStudy (anonymous):

OpenStudy (anonymous):

hello??

OpenStudy (anonymous):

@mathstudent55 can u help me please with number 1

OpenStudy (anonymous):

?

OpenStudy (mathstudent55):

Sorry I had to go away from my computer. I'm back.

OpenStudy (anonymous):

ok

OpenStudy (mathstudent55):

You have a 30-60-90 right triangle. The ratio of the lengths of the sides are short leg:long leg:hypotenuse 1:sqrt(3):2

OpenStudy (mathstudent55):

In your case, short leg = x long leg = y hypotenuse = 20

OpenStudy (anonymous):

how do u know this!?? its so hard lol

OpenStudy (mathstudent55):

Do you know the Pythagorean theorem?

OpenStudy (anonymous):

nope

OpenStudy (mathstudent55):

|dw:1354060175288:dw|

OpenStudy (mathstudent55):

Pythagorean Theorem In a right triangle, the sum of the squares of the lengths of the legs equals the square of the length of the hypotenuse. If the legs have lengths a and b, and the hypotenuse, h, then a^2 + b^2 = c^2

OpenStudy (anonymous):

so how do i write my answer out dnt do it too professinal bc i already got caught bc sum1 helped me but gave me the answers from the answer key! n if i do it one more time i get kick out :(

OpenStudy (mathstudent55):

Does that look familiar?

OpenStudy (anonymous):

a2+b2=c2 i already know about tht

OpenStudy (mathstudent55):

I'm not just giving answers, I'm trying to explain so you undestand.

OpenStudy (anonymous):

i know but im just saying n yes i do understand it

OpenStudy (mathstudent55):

|dw:1354060364994:dw| Look at the drawing. I drew an equilateral triangle (all sides have equal length) whose sides all measure 2.

OpenStudy (mathstudent55):

AC = 2, BC = 2, AB = 2

OpenStudy (anonymous):

OH AB add together

OpenStudy (mathstudent55):

D is the midpoint of AB, so AD = DB = 1 which is half of AB

OpenStudy (mathstudent55):

Yes, the two parts rthat measure 1 add up to 2

OpenStudy (anonymous):

yup

OpenStudy (mathstudent55):

Now look at the triangle on the left side, ADC

OpenStudy (anonymous):

yea its 2

OpenStudy (mathstudent55):

In an equilateral triangle, the sides have equal lengths and the angles have equal measures. All angles of an equilateral triangle measure 60

OpenStudy (anonymous):

oh no it s 3

OpenStudy (mathstudent55):

This meanse that angle A measures 60, angle B measures 60 and angle ACB (entire angle at top) also measure 60

OpenStudy (anonymous):

wait wer did the 60 come frm?

OpenStudy (mathstudent55):

In an equilateral triangle, all sides measure same, and all angles measur same.

OpenStudy (anonymous):

oh

OpenStudy (mathstudent55):

The sides can be any length. ALL are 6 cm long, all are 10 inches long, all are 20 miles long. They can be any length, but all sides are the same length

OpenStudy (anonymous):

to get the answer so they can all be equl right?

OpenStudy (mathstudent55):

In any triangle, all angles add up to 180 degrees

OpenStudy (mathstudent55):

SInce in an equilateral triangle all angles measure the same and all add up to 180, that means each one must be 60 degrees.

OpenStudy (anonymous):

oh

OpenStudy (mathstudent55):

That's how you knoe that angle A measures 60

OpenStudy (anonymous):

yea

OpenStudy (mathstudent55):

Now look again at the triangle at the left, triangle ADC. Angle A measures 60, the right angle measures 90, all angles add up to 180, so the angle at the top, angle ACD must measure 30. This means triangle ADC is a 30-60-90 triangle.

OpenStudy (anonymous):

so for number one wat number are we trying to find?? 60?

OpenStudy (anonymous):

so it adds up to 180

OpenStudy (mathstudent55):

In number 1 you're trying to find what number one calls x and y which in my first drawing are called a and b

OpenStudy (mathstudent55):

All angles add up to 180, but you're looking for the lengths of the sides, not measures of angles. You know the angles are 30, 60 and 90 in problem 1. The question is what are the lengths x and y?

OpenStudy (anonymous):

the lengths in number one are 20 and 30

OpenStudy (mathstudent55):

Actually, you are right. It does not state that one angle measure 60, so 60 is also an answer. But you still need to find x and y

OpenStudy (anonymous):

how do you find x and y then??

OpenStudy (mathstudent55):

In a 30-60-90 triangle, the hypotenus is twice the length of the short leg. Since the hypotenuse is 20, the short leg, x = 10

OpenStudy (anonymous):

so weer did u get that 60 and 90 frm if in number one it only has 20 and 30?

OpenStudy (mathstudent55):

The right angle on bottom left with the little square in tghe corner measures 90 degrees

OpenStudy (mathstudent55):

The angle on top measures 30 degrees. We're told that

OpenStudy (mathstudent55):

The angle that's left, on bottom right has to be 60

OpenStudy (mathstudent55):

Angles of triangle add up to 180 180 - 90 - 30 = 60

OpenStudy (mathstudent55):

ratio of hypotenuse to short leg is 2:1 Since hypotenuse = 20 2:1 = 20:x 2/1 = 20/x multiply both sides by x: 2x = 20 x = 10

OpenStudy (mathstudent55):

Ratio of hypotenuse to long leg is 2:sqrt(3) 2:sqrt(3) = 20:y 2/sqrt(3) = 20/y Multiply both sides by y (2y)/sqrt(3) = 20 Multiply both sides by sqrt(3) 2y = 20 sqrt(3) y = 10 sqrt(3)

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