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OpenStudy (anonymous):
Find the exact value by using a half-angle identity.
cos (5π/12)
I have no clue how to do this....
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OpenStudy (anonymous):
the formula is cos=+or- 1+cos/2 all over a square root
OpenStudy (anonymous):
so it will be…. 1 + cos(5pi/12)/2 all under a square root
OpenStudy (lukecrayonz):
@jim_thompson5910
OpenStudy (lukecrayonz):
@timo86m
OpenStudy (anonymous):
that makes absolutely no sense to me...
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OpenStudy (lukecrayonz):
@AccessDenied
OpenStudy (anonymous):
is that the final answer?
OpenStudy (anonymous):
no you need to solve it on you calculator
OpenStudy (anonymous):
ehhh I have an example problem for sin and the answer isn't an exact value and there's a heck of a lot more steps
jimthompson5910 (jim_thompson5910):
cos (5pi/12) = cos ((1/2)*(5pi/6))
cos (5pi/12) = sqrt( (1+cos(5pi/6))/2 )
cos (5pi/12) = sqrt( (1-sqrt(3)/2)/2 )
cos (5pi/12) = sqrt( 1/2-sqrt(3)/4 )
cos (5pi/12) = sqrt( (2-sqrt(3))/4 )
cos (5pi/12) = sqrt(1/4)*sqrt( 2-sqrt(3) )
cos (5pi/12) = (1/2)*sqrt( 2-sqrt(3) )
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OpenStudy (anonymous):
Thank you @jim_thompson5910 (:
jimthompson5910 (jim_thompson5910):
yw
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