Question

Hi all
L=C+C1+C2+C3+....+Cn
C=2*r* Π
C1=2*(r-X)* Π
C2=2*(r-2X)* Π
C3=2*(r-3X)* Π
...
Cn=2*(r-nX)*Π

How to find n?

Answer 1

i wish i could help but have no clue haha

Answer 2

\[(\frac{ C _{n} }{ 2\pi }-r)\frac{ 1 }{ x }=n\]

Not sure if this is what your looking for. I just used algebra to make an expression for n.

Answer 3

equation* not expression.

Answer 4

i spose L is known?

Answer 5

\[L=\sum_{i=0}^{n}2\pi(r-ix)\]

Answer 6

we can pull out constants; and split the other term to start with

Answer 7

\[L=\sum_{i=0}^{n}2\pi(r-ix)\]
\[L=2\pi\sum_{i=0}^{n}(r-ix)\]
\[\frac{L}{2\pi}=\sum_{i=0}^{n}(r-ix)\]
\[\frac{L}{2\pi}=\sum_{i=0}^{n}r-\sum_{i=0}^{n}ix\]
\[\frac{L}{2\pi}=r(n+1)-x\sum_{i=0}^{n}i\]
\[\frac{L}{2\pi}=r(n+1)-x\frac{(n+1)(0+n)}{2}\]

Answer 8

looks like we can multiply thru by 2 and solve the quadritic for n using the quadratic formula if need be

Answer 9

all but n are known

Answer 10

then by that last setup, you should be able to figure out the n

Answer 11

youre quite welcome :)