Question

name the axis of symmetry and and the coordinates of vertex y=x^2-4x-3

Answer 1

Can you complete the square of x^2-4x-3?

Answer 2

idk how

Answer 3

To complete the square, first divide the coefficient in front of x by 2 and then square it, then add and subtract it in to the expression

so (-4/2)^2=4

x^2-4x+4-4-3

the first 3 terms factor as (x-2)^2, combine the remaining constants

y=(x-2)^2-7

now its in vertex form y=a(x-h)^2+k where (h,k) is the vertex and x=h is the axis of symmetry

Answer 4

So vertex is (2,-7) axis of symmetry is x=2

Answer 5

thanks man i think im getting it now