Question

Solve for x:

8^x = 1/6root(2)

Answer 1

I'm guessing I should change the RHS to (1/2)^(1/6.) Am I right?

Answer 2

lol tkhunny saves the day again!

Answer 3

Hello to you as well, sasogeek

Answer 4

hi :)

Answer 5

First, I'm not clear on your notation. Is it \(8^{x} = \dfrac{1}{6}\sqrt{2}\) or maybe \(8^{x} = \sqrt[6]{2}\) or something else?

Answer 6

The latter.

Answer 7

Sorry. I don't know how to type expressions like this into the field.

Answer 8

Anyway..I imagine I'm supposed to end up with 2^3^x = (1/2)^(1/6)

Answer 9

And then 2^3x = 2^(-1/6)

Answer 10

No worries. Learning just a little LaTeX can go a long way. You just have to find other ways to communicate without it. Click the [Equation] button, below, and do some experimenting.

Answer 11

Alright, will do :). So...is the answer just (-1/6)/2?

Answer 12

Excellent! 2^(3x) is the real key to this problem's simplest solution.

Same bases! If they are to be equal, the exponents must be equal.

3x = -1/6 if we started with \(\dfrac{1}{\sqrt[6]{2}}\) or

3x = 1/6 if we started with \(\sqrt[6]{2}\) or

Answer 13

Oh...of course. So it's (-1/6)/3, or -1/18

Answer 14

haha Thank you very much for the medal sasogeek, however undeserved it may be!

Answer 15

Thank you for all of your help!

Answer 16

it is well deserved :) you worked your way through to get the answer ;) and u got it right as well :)

Answer 17

Well, actually I got it wrong and then tkhunny guided me towards the correct answer, but I'm glad you think so!

Answer 18

A good night to all!

Answer 19

Though I'm sure I'll be back.

Answer 20

sure he did :) and that was great of him/her lol
but at the end of the day, i think you deserve the medal for your effort :)

Answer 21

Well, once again, thank you very much!