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OpenStudy (anonymous):
I have a question regarding the sum stuff with the big sigma.
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OpenStudy (anonymous):
According to my book this is true:
\[\sum_{k=1}^{n}1=n\]
Why is this sum n and not 1 or 0 since there is nothing to sum?
OpenStudy (anonymous):
yep
OpenStudy (anonymous):
there is. The summation notation means that 1 is added n times.
So, it's 1+1+1+1+1+1+1+1...+1 {n times }=n
OpenStudy (anonymous):
or you could factorise quadratically but that would take way longer
OpenStudy (anonymous):
Why do I add the 1s since there is no index k?
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OpenStudy (anonymous):
obviously
OpenStudy (anonymous):
\[\sum_{k=1}^{n}1 = 1+1+1+1+1+......+1 =n\]
if there is no k, then there is none. k=1 simply means you start from first terms. in this case,it's 1
OpenStudy (anonymous):
the k can be omitted, actually.
OpenStudy (anonymous):
How?
OpenStudy (anonymous):
\[\sum_{k=1}^{n}=\sum_{1}^{n}\]
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OpenStudy (anonymous):
writing k is mostly a formality but in this case without the index, then we simply ignore it and just add up 1s n times
OpenStudy (anonymous):
Ok, now I think I get it.
Thank you Shadowys for your help.
OpenStudy (anonymous):
You're welcome :)
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