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Mathematics 22 Online
OpenStudy (anonymous):

I have a question regarding the sum stuff with the big sigma.

OpenStudy (anonymous):

According to my book this is true: \[\sum_{k=1}^{n}1=n\] Why is this sum n and not 1 or 0 since there is nothing to sum?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

there is. The summation notation means that 1 is added n times. So, it's 1+1+1+1+1+1+1+1...+1 {n times }=n

OpenStudy (anonymous):

or you could factorise quadratically but that would take way longer

OpenStudy (anonymous):

Why do I add the 1s since there is no index k?

OpenStudy (anonymous):

obviously

OpenStudy (anonymous):

\[\sum_{k=1}^{n}1 = 1+1+1+1+1+......+1 =n\] if there is no k, then there is none. k=1 simply means you start from first terms. in this case,it's 1

OpenStudy (anonymous):

the k can be omitted, actually.

OpenStudy (anonymous):

How?

OpenStudy (anonymous):

\[\sum_{k=1}^{n}=\sum_{1}^{n}\]

OpenStudy (anonymous):

writing k is mostly a formality but in this case without the index, then we simply ignore it and just add up 1s n times

OpenStudy (anonymous):

Ok, now I think I get it. Thank you Shadowys for your help.

OpenStudy (anonymous):

You're welcome :)

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