Two runners start 30 kilometers apart and run toward each other. They meet after 3 hours. One runner runs 2 kilometers per hour faster than the other runner. What rate do they run?
@Cpt.Sparz
your asked to find rate, so that's going to be your unknown: let x be the first, slower speed, and x+2 be the second faster speed. each of these rates run for 3 hrs should total 30 kms, so we have \[\large D_{Total}=D_{slow}+D_{fast}\] \[\large 30kms=[Rate_{slow}*time]+[Rate_{fast}*time]\] \[\large 30[kms] = x*3[hrs]+(x+2)*3[hrs]\] solve for x and the units should give you km/hr
Mathmuse is correct...
For these questions, distances can be added directly. Rates of speed cannot be added correctly so you usually have generate a formula with distance and break it into components as per the distance/speed/time relationship: |dw:1354118969852:dw|
But if you want the answer here: The sum of their speeds is (30 km)/(3 hr) = 10 kph. The difference of their speeds is 2 kph (from the problem statement). This has solutions like any other "sum and difference" problem. The faster runner is running (10 + 2)/2 = 6 kph. The slower runner is running (10 - 2)/2 = 4 kph.
I THINK THIS IS MY ANWERS 4 km/hr and 6 km/hr
instead of km use kph so 4 kph/hr and 6 kph/hr
kph=kilometers per hour
YES
IS CORRECT MY ANSWER
yes your answer is right!
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