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Mathematics 9 Online
OpenStudy (anonymous):

pre-calc help! picture is attached!!

OpenStudy (anonymous):

OpenStudy (btaylor):

You first can tell that it will be a factor of 8, since the first one is 8. Then, since the first one is 8, the exponent must be (n). This means that the first time, there is a 5^0, which is 1. Now, for the +/- switching, we know that it must be a multiple of -5, since that is the factor in between each turn. So the answer must be B.

OpenStudy (anonymous):

how would i solve this: Find the sum of the first 12 terms of the sequence. Show all work for full credit. 1, -4, -9, -14, . . .

OpenStudy (anonymous):

@BTaylor

OpenStudy (anonymous):

please help!!! @BTaylor

OpenStudy (anonymous):

@badi

OpenStudy (anonymous):

@@hartnn @TuringTest

OpenStudy (anonymous):

@ajprincess @.Sam.

OpenStudy (anonymous):

Find the sum of the first 12 terms of the sequence. Show all work for full credit. 1, -4, -9, -14, . . .

OpenStudy (ajprincess):

This is an a.p. Do u knw hw to find the sum of an arithmetic progression?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

@ajprincess

OpenStudy (ajprincess):

\[S_n=\frac{ n(a+l )}{ 2 }\] This formula is used to find the sum of n terms. Here a-first term l-last term of the series. 12th term is ur last term. so to find it use the following formula. \[T_{12}=a+(n-1)d\] d-common difference. d=-9-(-4) =-9+4 =-5 n=12 a=1. Can u do it @Sammy90210?

OpenStudy (anonymous):

no im confused. can u show me on this one, i have many more like this to do

OpenStudy (ajprincess):

Let me guide u step by step. d-common difference. It can be found by finding the difference between the two terms. Let me take the first term nd second term. d=-4-1 =-5 n=12 a=1 Plugging the values in \[T_{12}=a+(n-1)d\] \[=1+(12-1)*-5\] \[=1+(11*-5)\] \[=1-55\] \[=-54\]

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