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Solve the exponential equation shown below. 12=10^x+3 -9
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\[12=10^{x+3}-9\] ?
yes
Alright, first add the 9 to both sides
21=10^x+3
Right, now take \[\log _{10} \] of both sides
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idk how to do that on this kind
for 21 is it 1.322?
and -7 for the other side
\[\log _{10}21=\log _{10}10^{x+3}\]
The log and exponential on the right cancel out and you're left with \[\log _{10}21=x+3\]
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is it 1.322=-7
oh! okay i gotcha
now do i do log of 10 21?
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