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Help please? Solve: log2 (x+5) + log2 (x+1)=5
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@Hero can you help me out
\[log_a(x) + \log_a(y) = \log_a(xy)\]
I got an answer 3 but I want to know if I am correct
@hero
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@Hero log2(x+5)(x+1)=5 log2(x^2 +6x+5)=5 2^5=x^2+6x+5 32=x^2+6x+5 0=x^2+6x-27 0=(x-3)(x+9) x=3 & -9 solution is 3 because you can't have a -9
I was talking to someone and they said there was no solution that is why I was worried
x = 3 is the correct solution
so there is a solution thank God I did it correct then thank you so much for confirming
Make sure to use double parentheses for the first step: log_{2}((x+5)(x+1))=5
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