how would you find the slope of x=5
you cant
try picking 2 points on the line and finding the slope between them
This is what it says im so confused: identify the slope and graph the equation for x=5 and y=-3
2 different questions? or parts?
Well it has a.) then b.) So I'm guessing questions..
k, lets do the y=-3 first; can you name 2 points on the y=-3 line?
There isn't a graph..... but I'm guessing -1, -2?
that tells me that you are not aware of what the concepts are for these "equations", and its most likely becasue you are used to seeing a particular form
the line y=-3 has all points such that the y component is -3 (x,-3) for any value of x; soo; (-1,-3) and (5,-3) are 2 points in the y=-3 line
So you can pick any x.
correct, y=-3 only cares about the y part, x can be anything it wants to be if we apply that to the line x=5, what do you believe that would tell us?
The slope?
no, how wold we pick to points on the line x=5? what is important about any point of the line x=5
if we can pick 2 points, we can define a slope
The y-intercept ?
the line y=-3 only cares about the y value; all points (x,-3) are on the line for the other line x=5, we only care about the x values; all points (5,y) are on the line
The slope of any vertical line is undefined. Horizontal lines all have a slope of 0. Because x=5 is a purely vertical line, the slope is simply undefined. Do not confuse undefined with 0 as they are different.
So each line only cares for a certain value and x is always 0?
"So each line only cares for a certain value" yes, ignore the rest of your comment
iangu is giving you a definition that can be memorized, I am trying to prove the definitions
So x isn't always 0? But what about the rule y=mx+b?
Y=-3 is a horizontal line ( you can use (0,-3) as a reference point) and the slope is 0 because it is horizontal. Chances are the idea behind that lesson is to have you memorize these things. Proofs are only important in college and only for certain professors but tend to be complicated and unnecessary if not asked for. I am stating this out of current experience in calculus at UCF
thats is the form of a line that you are used to seeing; and it can be modified for the y=-3 form; but it cannot be modified for the x=5 form
That kind of makes sense... So then slope would always be 0?...
y=mx+b is merely the slope-intercept method of writing an equation and will NORMALLY tell you what the slope is, the problem is that like I said, vertical lines and horizontal lines are exceptions to the rule.
for y=-3, or any constant value; yes the slope is 0
for x=5, you can say that the slope is NOT EVEN zero
So that method doesn't always work... So my overall is what is the best way to REMEMBER how to find slope and y-intercept that will always work?
"any constant value" can be misleading. Any constant Y-value is a horizontal line with slope 0 while any constant X-value is a vertical line with an undefined slope
2 points on the x=5 line can be: (5,0) and (5,2) the slope between the points is:\[\frac{2-0}{5-5}=\frac20\]since division by 0 is not allowed, this is simply undefined
And that is a great proof for vertical slope
That makes a little sense. Thank you.
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